Sort a Python dictionary by value
Making use of the sorted() function, pass in a callable function/object to the key parameter to make comparison.
Using Lambda specify the value (index 1)
1
2
d = {'a': 4, 'b': 1, 'c': 10, 'd': 2}
sorted(d.items(), key=lambda x:x[1])
[(‘b’, 1), (‘d’, 2), (‘a’, 4), (‘c’, 10)]
Using Operator specify the value (index 1)
1
2
3
import operator
d = {'a': 4, 'b': 1, 'c': 10, 'd': 2}
sorted(d.items(), key=operator.itemgetter(1))
[(‘b’, 1), (‘d’, 2), (‘a’, 4), (‘c’, 10)]
Enable Jupyter notebook code autocomplete (‘Intellisense’)
Just add the line %config IPCompleter.greedy=True at the top of the nb file.
Then, you should be able to see available methods when pressing the TAB.
Named Tuple
The named tuple is from the Collections module and it helps create a class easily.
But as the name suggests, it is also immutable, just like the Tuple.
1
2
3
4
5
from collections import namedtuple
CAR = namedtuple('CAR', 'name colour age star')
car = CAR('bwm', 'red', 10, 'good')
print ('The car\'s name is {}, its colour is {} and the star of recommendation is {}'.format(car.name, car.colour, car.star))
The car’s name is bwm, its colour is red and the star of recommendation is good
